(x^2)+2.2x-42.35=0

Solution for (x^2)+2.2x-42.35=0 equation:

(x^2)+2.2x-42.35=0

a = 1; b = 2.2; c = -42.35;
Δ = b2-4ac
Δ = 2.22-4·1·(-42.35)
Δ = 174.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.2)-\sqrt{174.24}}{2*1}=\frac{-2.2-\sqrt{174.24}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.2)+\sqrt{174.24}}{2*1}=\frac{-2.2+\sqrt{174.24}}{2}
$